Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning

Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises: 34

Answer

The sequence converges to $e^2.$

Work Step by Step

By continuity of limits we may take the limit to the exponent of $e$. The limit of $\frac{2n}{n + 2}$ is 2. Hence the sequence converges to $e^2.$

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