Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 11 - Section 11.1 - Sequences - 11.1 Exercises: 18

Answer

$$a_n = \sin{(\frac{n\pi}{2})}$$

Work Step by Step

Our first term is $a_1 = 1$. The sequence resembles the relationship of $\sin(x)$ at evaluations of $x = n\frac{\pi}{2}$ as $n = 1, 2, 3, 4, \cdots.$ Hence $$a_n = \sin{(\frac{n\pi}{2})}$$
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