Answer
$\frac{3}{4-3i}$ = $\frac{12}{25}$ + $\frac{9i}{25}$
Work Step by Step
Multiply by the conjugate:
$\frac{3}{4-3i}$ $\times$ $\frac{4+3i}{4+3i}$
$\frac{(3\times4)+(3\times3i)}{4^{2}+3^{2}}$ = $\frac{12+9i}{25}$
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