Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

APPENDIX H - Complex Numbers - H Exercises: 10

Answer

$\frac{3}{4-3i}$ = $\frac{12}{25}$ + $\frac{9i}{25}$

Work Step by Step

Multiply by the conjugate: $\frac{3}{4-3i}$ $\times$ $\frac{4+3i}{4+3i}$ $\frac{(3\times4)+(3\times3i)}{4^{2}+3^{2}}$ = $\frac{12+9i}{25}$
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