Answer
$-\frac{5}{17}+\frac{14}{17}i$
Work Step by Step
$\frac{3+2i}{1-4i}$
$=\frac{3+2i}{1-4i}*\frac{1+4i}{1+4i}$
$=\frac{3(1+4i)+2i(1+4i)}{1^2+(4i)^2}$
$=\frac{3+12i+2i-8}{1+16}$
$=\frac{-5+14i}{17}$
$=-\frac{5}{17}+\frac{14}{17}i$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
APPENDIX H - Complex Numbers - H Exercises - Page A 64: 8
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