Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.7 Physical Applications - 6.7 Exercises - Page 468: 30

Answer

$1.4 \times 10^7 \ J$

Work Step by Step

The area of a slice is equal to $A(y)=(25)(15)=375$ We need to use the formula such as: $W=\int_a^b \rho g A(y) D(y) \ dy$. Plug in the above formula the given values to obtain: $W=\int_a^b \rho g A(y) D(y) \ dy\\=375 \int_0^{2} \rho g (3-y) \ dy\\=375 \times \rho g \times [3y-\dfrac{y^2}{2}]_0^2 \\=(375)(4) \rho g\\=(375) (1000) (9.81) (4)\\=1.4 \times 10^7 \ J$
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