Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.7 Physical Applications - 6.7 Exercises - Page 468: 27

Answer

$11484375 \ J$

Work Step by Step

We need to use the formula such as: $W=\int_a^b \rho g A(y) D(y) \ dy$. Plug in the above formula the given values to obtain: $W=\int \rho g A(y) D(y) \ dy\\=\int_0^{2.5} \rho g (2.5-y) (375) \ dy\\=3.125 \times \rho g \times 375\\=11484375 \ J$
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