Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 6 - Applications of Integration - 6.3 Volume by Slicing - 6.3 Exercises - Page 430: 17

Answer

$36 \pi \approx 152.05$

Work Step by Step

Since, the vertical slices solid are circular discs , so we will use the disk method to compute the volume of revolution of the curve. The volume of revolution of the curve can be expressed as: $V=\pi \int_p^q [f(x)]^2 dx\\=\pi \int_0^3 [2x]^2 \ dx \\=4 \pi \int_0^3 x^2 \ dx \\=4 \pi [\dfrac{27}{3}-0]_0^3 \\=36 \pi \approx 152.05$
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