Answer
$\dfrac{ 32}{3} m^3$
Work Step by Step
We have the area of an equilateral triangle is: $A(x)=(\sqrt 2 x)^2 =2 x^2$
The volume of a solid can be computed as:
$V=\int_a^b A(y) dy=\int_0^2 4 (2-y)^2 \ dy \\=|\dfrac{4(2-y)^3}{-3}|_0^2\\=\dfrac{4(2-2)^3}{-3}-\dfrac{4(2-0)^3}{-3} \\=\dfrac{ 32}{3} m^3$
