Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 5 - Integration - 5.3 Fundamental Theorem of Calculus - 5.3 Exercises: 29

Answer

$\int ^2 _0 (4x^3)dx = 16 $

Work Step by Step

$\int ^2 _0 (4x^3)dx = (4\frac{x^4}{4})|^2_0 = x^4|^2_0 =2^4 - 0^4 = 16 $
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