Answer
$$ = 2\ln 9 - 2\ln 4 + 2$$
Work Step by Step
$$\eqalign{
& \int_4^9 {\frac{{2 + \sqrt t }}{t}} dt \cr
& {\text{split the numerator}} \cr
& = \int_4^9 {\left( {\frac{2}{t} + \frac{{\sqrt t }}{t}} \right)} dt \cr
& {\text{writting }}\sqrt t {\text{ as }}{t^{1/2}} \cr
& = \int_4^9 {\left( {\frac{2}{t} + \frac{{{t^{1/2}}}}{t}} \right)} dt \cr
& = \int_4^9 {\left( {\frac{2}{t} + {t^{ - 1/2}}} \right)} dt \cr
& {\text{integrating using the logarithmic rule and the power rule for integration}} \cr
& \int_4^9 {\left( {\frac{2}{t} + {t^{ - 1/2}}} \right)} dt = \left. {\left( {2\ln \left| t \right| + \frac{{{t^{1/2}}}}{{1/2}}} \right)} \right|_4^9 \cr
& = \left. {\left( {2\ln \left| t \right| + 2{t^{1/2}}} \right)} \right|_4^9 \cr
& {\text{using The Fundamental Theorem}} \cr
& = \left( {2\ln \left| 9 \right| + 2{{\left( 9 \right)}^{1/2}}} \right) - \left( {2\ln \left| 4 \right| + 2{{\left( 4 \right)}^{1/2}}} \right) \cr
& {\text{simplify}} \cr
& = 2\ln 9 + 6 - 2\ln 4 - 4 \cr
& = 2\ln 9 - 2\ln 4 + 2 \cr} $$
