## Calculus: Early Transcendentals (2nd Edition)

$= \frac{1}{4}$
$\begin{gathered} \mathop {\lim }\limits_{x \to \,2} \,\,\,\frac{{\sin \,\left( {x - 2} \right)}}{{{x^2} - 4}} \hfill \\ \hfill \\ factoring\,\,the\,\,denominator\,\, \hfill \\ \hfill \\ = \mathop {\lim }\limits_{x \to \,2} \,\,\,\frac{{\sin \,\,\left( {x - 2} \right)}}{{\,\left( {x + 2} \right)\,\left( {x - 2} \right)}} \hfill \\ \hfill \\ rewriting \hfill \\ = \mathop {\lim }\limits_{x \to \,2} \,\,\,\frac{{\sin \,\,\left( {x - 2} \right)}}{{\,\left( {x + 2} \right)\,\left( {x - 2} \right)}} \hfill \\ \hfill \\ use\,\,the\,\,product\,\,rule\,\,for\,\,\,limits\, \hfill \\ \hfill \\ = \,\left( {\mathop {\lim }\limits_{x \to \,2} \,\,\,\frac{1}{{x + 2}}} \right)\,\left( {\mathop {\lim }\limits_{x \to \,2} \,\,\,\frac{{\sin \,x - 2}}{{x - 2}}} \right) \hfill \\ \hfill \\ evaluate \hfill \\ \hfill \\ = \,\left( {\frac{1}{{2 + 2}}} \right)\,\left( 1 \right) \hfill \\ \hfill \\ = \frac{1}{4} \hfill \\ \hfill \\ \end{gathered}$