Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 3 - Derivatives - 3.5 Derivatives of Trigonometric Functions - 3.5 Exercises: 42

Answer

\[y'' = - \cos x\]

Work Step by Step

\[\begin{gathered} y = \cos x \hfill \\ \hfill \\ differentiate\,\,to\,\,find\,\,y{\,^,} \hfill \\ \hfill \\ y' = - \sin x \hfill \\ \hfill \\ differentiate\,\,to\,\,find\,\,{y^,}^, \hfill \\ \hfill \\ y'' = \,{\left( { - \sin x} \right)^\prime } \hfill \\ \hfill \\ y'' = - \cos x \hfill \\ \end{gathered} \]
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