Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - Review Exercises: 34

Answer

$0$

Work Step by Step

$\lim _{z\rightarrow \infty }\left( e^{-2z}+\dfrac {2}{z}\right) =e^{-\infty }+\dfrac {2}{\infty }=\dfrac {1}{e^{\infty }}+\dfrac {2}{\infty }=0+0=0$
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