Answer
$0$
Work Step by Step
$\lim _{z\rightarrow \infty }\left( e^{-2z}+\dfrac {2}{z}\right) =e^{-\infty }+\dfrac {2}{\infty }=\dfrac {1}{e^{\infty }}+\dfrac {2}{\infty }=0+0=0$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - Review Exercises - Page 124: 34
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