Answer
$\dfrac {1}{2}$
Work Step by Step
$\lim _{x\rightarrow \infty }\dfrac {2x-3}{4x+10}=\lim _{x\rightarrow \infty }\dfrac {2-\dfrac {3}{x}}{4+\dfrac {10}{x}}=\dfrac {2-0}{4+0}=\dfrac {2}{4}=\dfrac {1}{2}$
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