Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises: 17

Answer

$\lim\limits_{x \to 1}{(4f(x))}=32$

Work Step by Step

$\lim\limits_{x \to 1}{(4f(x))}$ $\lim\limits_{x \to 1}{(4f(x))}=4\lim\limits_{x \to 1}{f(x)}$ We know that $\lim\limits_{x \to 1}{f(x)}=8$ So $\lim\limits_{x \to 1}{(4f(x))}=4\lim\limits_{x \to 1}{f(x)} = 4\times8=32$
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