Answer
$3$
Work Step by Step
$\lim _{b\rightarrow 2}\dfrac {3b}{\sqrt {4b+1}-1}=\dfrac {3\times 2}{\sqrt {4\times 2+1}-1}=\dfrac {6}{\sqrt {9}-1}=\dfrac {6}{3-1}=3$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 29
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
