Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 11 - Vectors and Vector-Valued Functions - 11.6 Calculus of Vector-Valued Functions - 11.6 Exercises: 12

Answer

$\textbf{r}'(t) = \langle sec^2(t), sec(t)tan(t), -2sin(t)cos(t)\rangle$

Work Step by Step

$\textbf{r}(t) = \langle f(t), g(t), h(t)\rangle$ $\textbf{r}'(t) = \langle f'(t), g'(t), h'(t)\rangle$ $\textbf{r}(t) = \langle tan(t), sec(t), cos^2(t)\rangle$ $\textbf{r}'(t) = \langle sec^2(t), sec(t)tan(t), -2sin(t)cos(t)\rangle$
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