Answer
$\textbf{r}'(t) = \langle 0, -6sin(2t), 6cos(3t)\rangle$
Work Step by Step
$\textbf{r}(t) = \langle f(t), g(t), h(t)\rangle$
$\textbf{r}'(t) = \langle f'(t), g'(t), h'(t)\rangle$
$\textbf{r}(t) = \langle 4, 3cos(2t), 2sin(3t)\rangle$
$\textbf{r}'(t) = \langle 0, -6sin(2t), 6cos(3t)\rangle$