Answer
$$\lim _{x \rightarrow 0^{+}} \frac{1}{\ln x}=0$$
Work Step by Step
Given $$\lim _{x \rightarrow 0^{+}} \frac{1}{\ln x}$$
Since
\begin{align*}
\lim _{x \rightarrow 0^{+}} \frac{1}{\ln x}&= \frac{\lim _{x \rightarrow 0^{+}}1}{\lim _{x \rightarrow 0^{+}}\ln x}\\
&= \frac{ 1}{-\infty}\\
&=0
\end{align*}