Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.2 Exponential Functions and Their Derivatives - 6.2 Exercises: 92

Answer

$e^{\sin\theta} +C$

Work Step by Step

Let $u=\sin \theta$. Then $du=\cos\theta\ d\theta$. $\int e^{\sin\theta}\cos\theta\ d\theta$ $=\int e^u du$ $=e^u+C$ $=e^{\sin\theta} +C$
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