## Calculus 8th Edition

$V= \frac{\pi}{2}(e^{2}-1)=10.0359$
The volume of the solid obtained by rotating the region under the curve $y=e^{x}$ From 0 to 1 about the x-axis is equal to $V=\int_{0}^{1} A(x) dx$ $=\int_{0}^{1} \pi e^{2x} dx$ $=\pi(\frac{e^{2x}}{2})_{0}^{1}$ Hence, $V= \frac{\pi}{2}(e^{2}-1)=10.0359$