Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 5 - Applications of Integration - 5.4 Work - 5.4 Exercises - Page 387: 23

Answer

$1.06{\times}{10^{6}}$ $J$

Work Step by Step

A rectangular slice of water $Δx$ $m$ thick and lying $x$ $m$ above the bottom has width $x$ $m$ and volume $8xΔx$ $m^{3}$. It weighs about $(9.8\times1000)(8xΔx)$ $N$, and must be lifted $(5-x)$ $m$ by the pump, so the work needed is about $(9.8{\times}{10}^{3})(5-x)(8xΔx)$ $J$ The total work required is $W$ $\approx$ $\int_0^3(9.8{\times}{10}^{3})(5-x)(8xdx)$ $\approx$ $(9.8{\times}{10}^{3})\left[20x^{2}-\frac{8}{3}{x^{3}}\right]_0^3$ $\approx$ $1.06{\times}{10^{6}}$ $J$
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