Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 3 - Applications of Differentiation - 3.9 Antiderivatives - 3.9 Exercises - Page 283: 27

Answer

$$ f^{\prime \prime\prime}(t)=12+\sin t $$ $\Longrightarrow $ $$ f(x) =2 t^{3}+ \cos t +C t^{2}+D t+E $$ where $C,D $ and $E$ are arbitrary constants .

Work Step by Step

$$ f^{\prime \prime\prime}(t)=12+\sin t $$ The general anti-derivative of $ f^{\prime \prime\prime}(t)=12+\sin t $ is $$ f^{\prime\prime}(x) =12t -\cos t +C_{1} \\ $$ Using the anti-differentiation rules once more, we find that $$ f^{\prime}(x) =6t^{2}- \sin t +C_{1} t+D $$ Using the anti-differentiation rules once more, we find that $$ f(x) =2 t^{3}+ \cos t +C t^{2}+D t+E $$ where $C=\frac{1}{2}C_{1},D, E$ are arbitrary constants .
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