Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 3 - Applications of Differentiation - 3.9 Antiderivatives - 3.9 Exercises - Page 283: 28

Answer

$$ f^{\prime \prime \prime}(t)=\sqrt{t}-2 \cos t $$ The required function is $$ f(x) =\frac{8}{105}t^{\frac{7}{2}} -2 \sin t +C t^{2}+D t+E $$ where $C,D, E$ are arbitrary constants .

Work Step by Step

$$ f^{\prime \prime \prime}(t)=\sqrt{t}-2 \cos t $$ The general anti-derivative of $ f^{\prime \prime \prime}(t)=\sqrt{t}-2 \cos t $ is $$ f^{\prime\prime}(x) =\frac{2}{3}t^{\frac{3}{2}} -2 \sin t +C_{1} \\ $$ Using the anti-differentiation rules once more, we find that $$ f^{\prime}(x) =\frac{4}{15}t^{\frac{5}{2}} +2 \cos t +C_{1} t+D $$ Using the anti-differentiation rules once more, we find that $$ f(x) =\frac{8}{105}t^{\frac{7}{2}} -2 \sin t +C t^{2}+D t+E $$ where $C=\frac{1}{2}C_{1},D, E$ are arbitrary constants .
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