Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.8 Related Rates - 2.8 Exercises - Page 186: 21

Answer

$-1.6$ $cm/min$

Work Step by Step

$A$ = $\frac{1}{2}bh$ where $b$ is the base and $h$ is the altitude We are given that $\frac{dh}{dt}$ = $1$ $cm/min$ $\frac{dA}{dt}$ = $2$ $cm^{2}/min$ Product rule $\frac{dA}{dt}$ = $\frac{1}{2}(b\frac{dh}{dt}+h\frac{db}{dt})$ $h$ = $10$ and $A$ = $100$ $100$ = $\frac{1}{2}(b)(10)$ $b$ = $20$ so $2$ = $\frac{1}{2}[20(1)+10\frac{db}{dt}]$ $\frac{db}{dt}$ = $-1.6$ $cm/min$
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