Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.8 Related Rates - 2.8 Exercises - Page 186: 19

Answer

$8.99$ $ft/s$

Work Step by Step

we are given that $\frac{dx}{dt}$ = $4$ $ft/s$ $\frac{dy}{dt}$ = $5$ $ft/s$ $z^{2}$ = $(x+y)^{2}+500^{2}$ $2z\frac{dz}{dt}$ = $2(x+y)(\frac{dx}{dt}+\frac{dy}{dt})$ 15 minutes after the woman starts we have $x$ = $(4 ft/s)(20min)(60s/min)$ = $4800$ $ft$ $y$ = $5(15)(60)$ = $4500$ $Z$ = $\sqrt {(4800+4500)^{2}+500^{2}}$ = $9313.43$ $\frac{dz}{dt}$ = $\frac{x+y}{z}(\frac{dx}{dt}+\frac{dy}{dt})$ $\frac{dz}{dt}$ = $\frac{4800+4500}{9313.43}(4+5)$ = $8.99$ $ft/s$
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