Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.5 The Chain Rule - 2.5 Exercises - Page 159: 76

Answer

a) $v(t)=-Aw\sin(wt+\delta)$ b) $t=\frac{k\pi-\delta }{w}$ where $k \in \mathbb Z$.

Work Step by Step

$a)$ $$v(t)=s'(t)=-A(wt+\delta)'\sin(wt+\delta)$$ $$v(t)=s'(t)=-Aw\sin(wt+\delta)$$ $b)$ $$-Aw\sin(wt+\delta)=0 \to \sin(wt+\delta)=0 \to wt+\delta=k\pi \to t=\frac{k\pi-\delta }{w}$$ where $k \in \mathbb Z$.
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