Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.5 The Chain Rule - 2.5 Exercises - Page 159: 71

Answer

96

Work Step by Step

$F(x)=f(3f(4f(x)))$ _____(1) Using chain rule differentiating (1) with respect to $x$ $F^{'}(x)=f^{'}(3f(4f(x)))\cdot [3f(4f(x))]^{'}$ Using chain rule $F^{'}(x)=f^{'}(3f(4f(x)))\cdot [3f^{'}(4f(x))]\cdot [4f(x)]^{'}$ $F^{'}(x)=f^{'}(3f(4f(x)))\cdot [3f^{'}(4f(x))]\cdot 4f^{'}(x)$ $F^{'}(0)=f^{'}(3f(4f(0)))\cdot [3f^{'}(4f(0))]\cdot [4f^{'}(0)]$ Using given data $f(0)=0\;,\;f^{'}(0)=2$ $F^{'}(0)=f^{'}(3f(0))\cdot [3f^{'}(0)]\cdot [4 \times 2]$ $F^{'}(0)=f^{'}(0)\cdot [3\times2]\cdot [4\times 2]$ $F^{'}(0)=2\times3\times2\times4\times2$ $F^{'}(0)=96$ Hence $F^{'}(0)=96$.
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