Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - P.1 - Graphs and Models - Exercises: 46

Answer

y=$\sqrt (25-x^{2}$) x-intercepts at (5,0) and (-5.0) y-intercept at (0,5)
1478638141

Work Step by Step

Find Intercepts: x-int 0=$\sqrt (25-x^{2}$) x=5,-5 x-intercepts at (5,0) and (-5.0) y-int y=$\sqrt (25-0^{2}$) y=5,-5 y-intercept at (0,5) Find Symmetry: Substitute -x for x. If equation is equivalent, graph is symmetric to y-axis. y=$\sqrt (25-(-x)^{2}$) y=$\sqrt (25-x^{2}$) Equations are equivalent, so function is symmetric to y-axis. Substitute -y for y. If equation is equivalent, graph is symmetric to x-axis. (-y)=$\sqrt (25-x^{2}$) y=-$\sqrt (25-x^{2}$) Equations are not equivalent, so not symmetric to x-axis. Substitute -y for y and -x for x. If equation is equivalent, graph is symmetric to origin. (-y)=$\sqrt (25-(-x)^{2}$) y=-$\sqrt (25-x^{2}$) Equations are not equivalent, so not symmetric to origin.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.