## Calculus 10th Edition

$x$-intercept$=4$ $y$-intercept$=2$
$y=\dfrac{2-\sqrt{x}}{5x+1}$ Find the $y$-intercept by setting $x$ equal to zero and solving for $y$: $x=0$ $y=\dfrac{2-\sqrt{0}}{5(0)+1}=\dfrac{2-0}{0+1}=2$ $y$-intercept$=2$ Find the $x$-intercept by setting $y$ equal to zero and solving for $x$: $y=0$ $0=\dfrac{2-\sqrt{x}}{5x+1}$ $(0)(5x+1)=2-\sqrt{x}$ $2-\sqrt{x}=0$ $\sqrt{x}=2$ $x=2^{2}$ $x=4$ $x$-intercept$=4$