Answer
$f’(x) = 3x^2 $
Work Step by Step
$f(x) = (x-2)(x^2+2x+4) $
$f’(x) = (1)(x^2+2x+4)+(x-2)(2x+2) $
$f’(x) = x^2+2x+4+2x^2+2x-4x-4 $
$f’(x) = 3x^2 $
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