Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.4 The Product And Quotient Rules - Exercises Set 2.4 - Page 147: 4

Answer

$f’(x) = 3x^2 $

Work Step by Step

$f(x) = (x+1)(x^2-x+1) $ $f’(x) = (1)(x^2-x+1)+(x+1)(2x-1) $ $f’(x)= x^2-x+1+2x^2-x+2x-1 $ $f’(x) = 3x^2 $
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