Answer
$\begin{bmatrix}
2&-4\\
-3&5
\end{bmatrix}$
Work Step by Step
$[T(\vec{d_1})_B\ \ \ \ T(\vec{d_2})_B\ \ \ T(\vec{d_3})_B ]=\begin{bmatrix}
2&-4\\
-3&5
\end{bmatrix}$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 5 - Eigenvalues and Eigenvectors - 5.4 Exercises - Page 295: 2
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