Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 2 - Matrix Algebra - 2.4 Exercises - Page 123: 11

Answer

True,false

Work Step by Step

(a) True. This is named in the section Addition and Scalar Multiplication. I say you try it for small matrices $A_{1}, A_{2}, B_{1},$ and $B_{2}$ if it doesn't seem obvious to you. (b) False.we know that $A$ and $B$ can be multiplied iff the number of columns of $A$ is equal to the number of rows of $B .$ But the number of columns of $A$ depends on the number of columns of both $A_{11}$ and $A_{12}$ and the number of rows of $B$ depends on the number of rows of $B_{1}$ and $B_{2} .$ These don't have to be the same just since there are the same number of column partitions of $A$ as row partitions of $B$. As a concrete counterexample, let \[ A=\left[\begin{array}{cc|c} 1 & 2 & -4 \\ \hline 3 & 6 & -7 \\ 4 & -5 & 1 / 2 \end{array}\right] \quad \text { and } \quad B=\left[\begin{array}{cccc} 1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 1 & 0 \\ \hline 2 & 2 & 2 & 2 \\ -2 & -2 & -2 & -2 \end{array}\right] \] We can explicitly see that though $A$ has exactly the same number of column partitions as $B$ has row partitions $(2), A$ DOESN'T have the same number of columns as $B$ has rows. So $A$ and $B$ cannot be multiplied as $A B$ (they also cannot be multiplied as $B A$ in this case, as you can easily $y$ confirm
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