Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 76

Answer

$8+2\sqrt{15}$

Work Step by Step

$(\sqrt3+\sqrt5)^2$= $(\sqrt{3}+\sqrt5)(\sqrt{3}+\sqrt5)$ Use the FOIL method to multiply the binomial. Multiply the First terms, the Outside terms, the Inside terms, and the Last terms. $(\sqrt{3}\times\sqrt{3})+(\sqrt3\times\sqrt5)+(\sqrt3\times\sqrt5)+(\sqrt5\times(\sqrt5))$ Simplify. $3+\sqrt{15}+\sqrt15+5$ Combine like terms/like radicals. $8+2\sqrt{15}$
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