Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 67

Answer

$-14$

Work Step by Step

RECALL: (i) $(a+b)(a-b) = a^2-b^2$ (ii) $\sqrt{a}^2=a, a \ge0$ Use rule (i) above to obtain: $=\sqrt{11}^2-5^2 \\=\sqrt{11}^2-25$ Use rule (ii) above to obtain: $=11-25 \\=-14$
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