Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 69

Answer

$y^3-6y^2+13y-12$

Work Step by Step

Using the Distributive Property, the given expression, $ (y-3)(y^2-3y+4) ,$ is equivalent to \begin{array}{l}\require{cancel} y(y^2)+y(-3y)+y(4)-3(y^2)-3(-3y)-3(4) \\\\= y^3-3y^2+4y-3y^2+9y-12 \\\\= y^3+(-3y^2-3y^2)+(4y+9y)-12 \\\\= y^3-6y^2+13y-12 .\end{array}
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