Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.2 - Multiplying Polynomials - Exercise Set: 59

Answer

$x^2-2x-15$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the Distributive Property, the given expression, $ (x+3)(x-5) ,$ is equivalent to \begin{array}{l}\require{cancel} x(x)+x(-5)+3(x)+3(-5) \\\\= x^2-5x+3x-15 \\\\= x^2-2x-15 .\end{array}
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