Answer
y+$\frac{1}{4}$=-1(x+4)
y=-x-$\frac{17}{4}$
Work Step by Step
y-y$_1$=m(x-x$_1$)
y-(-$\frac{1}{4}$)=-1(x-(-4))
y+$\frac{1}{4}$=-1(x+4)
This is point-slope form. Now isolate y to find slope-intercept form.
y+$\frac{1}{4}$=-x-4
y+$\frac{1}{4}$-$\frac{1}{4}$=-x-4-$\frac{1}{4}$
y=-x-$\frac{16}{4}$-$\frac{1}{4}$
y=-x-$\frac{17}{4}$
This is slope-intercept form.