Answer
y+2=-$\frac{2}{3}$(x-6)
y=-$\frac{2}{3}$x+2
Work Step by Step
y-y$_1$=m(x-x$_1$)
y-(-2)=-$\frac{2}{3}$(x-6)
y+2=-$\frac{2}{3}$(x)-$\frac{2}{3}$(-6)
This is point-slope form. Now isolate y to find slope-intercept form.
y+2=-$\frac{2}{3}$x+$\frac{12}{3}$
y+2=-$\frac{2}{3}$+4
y+2-2=-$\frac{2}{3}$x+4-2
y=-$\frac{2}{3}$x+2
This is slope=intercept form.