Answer
z=$\frac{29}{6}$
Work Step by Step
Add $\frac{5}{2}$ to both sides of the equation to isolate the variable.
$\frac{7}{3}$=-$\frac{5}{2}$+z
$\frac{7}{3}$+$\frac{5}{2}$=z
$\frac{7(2)}{3(2)}$+$\frac{5(3)}{2(3)}$=z
$\frac{14}{6}$+$\frac{15}{6}$=z
$\frac{29}{6}$=z
Check the answer.
$\frac{7}{3}$=-$\frac{5}{2}$+($\frac{29}{6}$)
$\frac{7}{3}$=-$\frac{15}{6}$+$\frac{29}{6}$
$\frac{7}{3}$=$\frac{14}{6}$
$\frac{7}{3}$=$\frac{7}{3}$
