Introductory Algebra for College Students (7th Edition)

r=-$\frac{13}{10}$
Subtract $\frac{3}{5}$ from both sides of the equation to isolate the variable. r+$\frac{3}{5}$=-$\frac{7}{10}$ r=-$\frac{7}{10}$-$\frac{3}{5}$ r=-$\frac{7}{10}$-$\frac{6}{10}$ r=-$\frac{13}{10}$ Check the answer. (-$\frac{13}{10}$)+$\frac{3}{5}$=-$\frac{7}{10}$ -$\frac{13}{10}$+$\frac{6}{10}$=-$\frac{7}{10}$ -$\frac{7}{10}$=-$\frac{7}{10}$