Answer
$\dfrac{\sqrt[3]{6}}{2}$
Work Step by Step
RECALL:
For any real number $a$,
$\sqrt[3]{a^3}= a$
Rationalize the denominator by multiplying $2$ to both the numerator and the denominator of the radicand.
Simplify using the rule above to obtain:
$\require{cancel}
=\sqrt[3]{\dfrac{3(2)}{4(2)}}
\\=\sqrt[3]{\dfrac{6}{8}}
\\=\sqrt[3]{\dfrac{6}{2^3}}
\\=\frac{1}{2}\sqrt[3]{6}
\\=\dfrac{\sqrt[3]{6}}{2}$
