Answer
$\displaystyle \frac{3\sqrt[4]{x^{3}y}}{x^{2}y}$
Work Step by Step
In the denominator, apply
$\sqrt[n]{a}\times\sqrt[n]{b}=\sqrt[n]{ab},\qquad$ and $\sqrt[n]{a^{n}}=(\sqrt[n]{a})^{n}=a$ (for positive a).
$\sqrt[4]{x^{5}y^{3}}=\sqrt[4]{x^{4}\times xy^{3}}=\sqrt[4]{x^{4}}\times\sqrt[4]{xy^{3}}=x\sqrt[4]{xy^{3}}$
we rationalize so that we get $\sqrt[4]{x^{4}y^{4}}$=$xy$ in the numerator
$\displaystyle \frac{3}{x\sqrt[4]{xy^{3}}} \displaystyle \color{red}{ \cdot\frac{\sqrt[4]{x^{3}y}}{\sqrt[4]{x^{3}y}} }\qquad$ (rationalize)
$=\displaystyle \frac{3\sqrt[4]{x^{3}y}}{x\sqrt[4]{x^{4}y^{4}}}$
$=\displaystyle \frac{3\sqrt[4]{x^{3}y}}{x\times xy}$
$=\displaystyle \frac{3\sqrt[4]{x^{3}y}}{x^{2}y}$
