Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 512: 57

Answer

$g(2)=-2$ $g(1)=0$ $g(0)=2$.

Work Step by Step

The given function is $g(x)=-\sqrt[3] {8x-8}$ Plug $x=2$ into the function. $g(2)=-\sqrt[3] {8(2)-8}$ Simplify. $g(2)=-\sqrt[3] {16-8}$ $g(2)=-\sqrt[3] {8}$ $g(2)=-\sqrt[3] {2^3}$ $g(2)=-2$ Plug $x=1$ into the function. $g(1)=-\sqrt[3] {8(1)-8}$ Simplify. $g(1)=-\sqrt[3] {8-8}$ $g(1)=-\sqrt[3] {0}$ $g(1)=-0$ $g(1)=0$ Plug $x=0$ into the function. $g(0)=-\sqrt[3] {8(0)-8}$ Simplify. $g(0)=-\sqrt[3] {0-8}$ $g(0)=-\sqrt[3] {-8}$ $g(0)=-\sqrt[3] {(-2)^3}$ $g(0)=-(-2)$ $g(0)=2$.
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