Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.1 - Radical Expressions and Functions - Exercise Set - Page 512: 56

Answer

$f(30)=3$ $f(11)=2$ $f(2)=-1$ $f(-122)=-5$.

Work Step by Step

The given function is $f(x)=\sqrt[3] {x-3}$ Plug $x=30$ into the function. $f(30)=\sqrt[3] {30-3}$ Simplify. $f(30)=\sqrt[3] {27}$ $f(30)=\sqrt[3] {3^3}$ $f(30)=3$ Plug $x=11$ into the function. $f(11)=\sqrt[3] {11-3}$ Simplify. $f(11)=\sqrt[3] {8}$ $f(11)=\sqrt[3] {2^3}$ $f(11)=2$ Plug $x=2$ into the function. $f(2)=\sqrt[3] {2-3}$ Simplify. $f(2)=\sqrt[3] {-1}$ $f(2)=\sqrt[3] {(-1)^3}$ $f(2)=-1$ Plug $x=-122$ into the function. $f(-122)=\sqrt[3] {-122-3}$ Simplify. $f(-122)=\sqrt[3] {-125}$ $f(-122)=\sqrt[3] {(-5)^3}$ $f(-122)=-5$.
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