Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set: 20

Answer

$a_{12}=-8,192$

Work Step by Step

RECALL: The $n^{th}$ term ($a_n$) of a geometric sequence can be found using the formula: $a_n= a_1 \cdot r^{n-1}$ where $a_1$ = first term r = common ratio Use the formula above and the give values of the first term and the common ratio to obtain: $a_n=4 \cdot (-2)^{n-1} \\a_{12}=4 \cdot (-2)^{12-1} \\a_{12}=4 \cdot (-2)^{11} \\a_{12}=4 \cdot (-2048) \\a_{12}=-8,192$
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