Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 854: 57

Answer

$\dfrac{257}{999}$

Work Step by Step

Sum of the first $n$ terms terms of a geometric sequence can be calculated as: $s_n=\dfrac{a_1}{(1-r)}$ $r$ refers to common ratio and $r=\dfrac{1}{1000}=0.01$ and $S_n=0.\overline{257}$ Apply the formula. $s_n=\dfrac{0.257}{(1-0.001)}=\dfrac{0.257}{0.999}=\dfrac{257}{999}$
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