Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set: 13

Answer

The first six terms are: $\frac{5}{2}, 2, \frac{3}{2}, 1, \frac{1}{2}, 0$

Work Step by Step

The next five terms f the sequence can be found by adding the common difference to obtain: $a_1=\frac{5}{2} \\a_2=\frac{5}{2}+(-\frac{1}{2})=\frac{4}{2}=2 \\a_3=.2+(-\frac{1}{2})=\frac{3}{2} \\a_4=\frac{3}{2}+(-\frac{1}{2})=\frac{2}{2}=1 \\a_5=1+(-\frac{1}{2}) = \frac{1}{2} \\a_6=\frac{1}{2}+(-\frac{1}{2})=0$
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