Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set: 14

Answer

$a_1=\frac{3}{4} \\a_2=\frac{1}{2} \\a_3 =\frac{1}{4} \\a_4 =0 \\a_5 =-\frac{1}{4} \\a_6 =-\frac{1}{2}$

Work Step by Step

The next five terms f the sequence can be found by adding the common difference to obtain: $a_1=\frac{3}{4} \\a_2=\frac{3}{4}+(−\frac{1}{4})=\frac{2}{4}=\frac{1}{2} \\a_3 = \frac{2}{4}+ (-\frac{1}{4})=\frac{1}{4} \\a_4 = \frac{1}{4}+(-\frac{1}{4})=0 \\a_5 = 0 +(-\frac{1}{4})=-\frac{1}{4} \\a_6 = -\frac{1}{4}+(-\frac{1}{4}) = -\frac{2}{4}=-\frac{1}{2}$
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